2c^2-5=-9c

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Solution for 2c^2-5=-9c equation:


Simplifying
2c2 + -5 = -9c

Reorder the terms:
-5 + 2c2 = -9c

Solving
-5 + 2c2 = -9c

Solving for variable 'c'.

Reorder the terms:
-5 + 9c + 2c2 = -9c + 9c

Combine like terms: -9c + 9c = 0
-5 + 9c + 2c2 = 0

Factor a trinomial.
(-5 + -1c)(1 + -2c) = 0

Subproblem 1

Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5

Subproblem 2

Set the factor '(1 + -2c)' equal to zero and attempt to solve: Simplifying 1 + -2c = 0 Solving 1 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2c = 0 + -1 -2c = 0 + -1 Combine like terms: 0 + -1 = -1 -2c = -1 Divide each side by '-2'. c = 0.5 Simplifying c = 0.5

Solution

c = {-5, 0.5}

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